emu8086编程计算
(w1-(w2*w3+w4-25000))/w5=w6设置w1=30000,w2=50,w3=800,w4=10000,w5=1000
完整的程序:
data segment w1 dw 30000 w2 dw 50 w3 dw 800 w4 dw 10000 w5 dw 1000 w6 dw 0 data ends stacks segment stack 'stack' dw 128 dup(0) stacks ends code segment assume cs:code,ds:data,ss:stacks start: mov ax, data mov ds, ax mov es, ax movax,w2 imul w3 addax, w4 subax,25000 pushax movax, w1 popdx subax,dx cwd idiv w5 mov w6,ax mov ax, 4c00h int 21h code ends end start
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