八年级上册数学题
[(x+2y²)-(x+2y)(x-2y)+2y(x-2y)]÷2y
解:原式=【x^2+4xy+4y^2-(x^2-4y^2)+2xy-4y^2】/2y(我怀疑(x+2y²)应该是(x+2y)²!)
=[x^2+4xy+4y^2-x^2+4y^2+2xy-4y^2]/2y
=[6xy+4y^2]/2y
=2y(3x+2y)/2y
=3x+2y
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[(x+2y²)-(x+2y)(x-2y)+2y(x-2y)]÷2y
解:原式=【x^2+4xy+4y^2-(x^2-4y^2)+2xy-4y^2】/2y(我怀疑(x+2y²)应该是(x+2y)²!)
=[x^2+4xy+4y^2-x^2+4y^2+2xy-4y^2]/2y
=[6xy+4y^2]/2y
=2y(3x+2y)/2y
=3x+2y