五个一维数组如果转化为一个二维数组（用c语言来实现）
已知五个一维数组：a[8]={1,2,3,4,5,6,7,8}b[8]={2,3,4,5,6,7,8,9}c[8]={3,4,5,6,7,8,1,2}d[8]={4,5,6,7,8,1,2,3}e[8]={5,6,7,8,3,5,7,5}想要得到新的二维数组是：f[8][5]={{1,2,4,3,5},{2,3,4,5,6},{3,4,5,6,7},{4,5,6,7,8},{5,6,7,8,3},{,6,7,8,1,5},{7,8,1,2,7},{8,9,2,3,5}}用c语言如何实现详细说明：新的二维数组8行5列第一列二维数组的元素{1,2,4,3,5}分别对应已知五个一维数组的第一个元素第二列二维数组的元素{2,3,4,5,6}分别对应已知五个一维数组的第二个元素以此类推...............................................第八列二维数组的元素{8,9,2,3,5}分别对应已知五个一维数组的第八个元素
简单的一个循环就可以实现////防重复3243685983976984375698326832587326587326598326532932564365332593259864385298359832587432658732154825679068709765873642156843576283435：
#include <stdio.h> int main() { int a[8] = { 1, 2, 3, 4, 5, 6, 7, 8 }; int b[8] = { 2, 3, 4, 5, 6, 7, 8, 9 }; int c[8] = { 3, 4, 5, 6, 7, 8, 1, 2 }; int d[8] = { 4, 5, 6, 7, 8, 1, 2, 3 }; int e[8] = { 5, 6, 7, 8, 3, 5, 7, 5 }; int f[8][5]; int i,j; for(i=0; i<8; i++) { f[i][0] = a[i]; f[i][1] = b[i]; f[i][2] = c[i]; f[i][3] = d[i]; f[i][4] = e[i]; } ///输出结果 for(i=0; i<8; i++) { for(j = 0; j < 5; j++) printf("%2d", f[i][j]); printf(" "); } return 0; }
测试结果
