请问我这个程序出现‘带有下标的赋值维度不匹配’的问题该怎么解决
% The model parameters are from Ref.[130]
close all
clear all
clc
tic
%the model parameters
N=2; % number of teeth
Kt=6e8; % tangential cutting force coefficient (N/m^2)
Kn=2e8; % normal cutting force coefficient (N/m^2)
w0=922*2*pi; % angular natural frequency (rad/s)
zeta=0.011; % relative damping (1)
m_t=0.03993; % mass (kg)
aD=0.1; % radial immersion ratio a/D
up_or_down=-1; % 1:up-milling, -1:down-milling
if up_or_down==1 % up-milling
fist=0; % start angle
fiex=acos(1-2*aD); % exit angle
elseif up_or_down==-1 % down-milling
fist=acos(2*aD-1); % start angle
fiex=pi; % exit angle
end
stx=200; % steps of spindle speed
sty=100; % steps of depth of cut
w_st=0e-3; % starting depth of cut (m)
w_fi=10e-3; % final depth of cut (m)
o_st=5e3; % starting spindle speed (m)
o_fi=25e3; % final spindle speed (rpm)
RVA=0.05; % RVA
RVF=0.1; % RVF
k=40*N/RVF; % number of discretization interval over one period
syms t
for i=1:k
c_i=k/(2*pi)*quadl('sin',(i-1)*2*pi/k,(i)*2*pi/k); % Eq. (3-26)
m(i)=floor(k*RVF*(1-RVA*c_i)/N+0.5); % Eq. (3-24)
wb(i)=k*RVF*(1-RVA*c_i)/N+0.5-m(i); % Eq. (3-27)
wa(i)=m(i)+0.5-k*RVF*(1-RVA*c_i)/N; % Eq. (3-27)
end
% the computational parameters
M=max(m); % Eq. (3-4)
D=zeros(3*M+6,3*M+6); % matrix D
d=ones(3*M+3,1);
d(1:6)=0;
D=D+diag(d,-3);
D(7,1)=1;
D(8,2)=1;
D(9,3)=1;
% discretization of the specific cutting force coefficient h(t)
for i=1:k+1
hxx(i)=0;
hxy(i)=0;
hxz(i)=0;
hyx(i)=0;
hyy(i)=0;
hyz(i)=0;
hzx(i)=0;
hzy(i)=0;
hzz(i)=0;
u(i)=2*pi/60*(i*60/k/RVF+60*RVA/(RVF*2*pi)*(1-cos(i*2*pi/k)));
for j=1:N % loop for tooth j
fi(j)=u(i)+(j-1)*2*pi/N; % Eq.(3-6)
fi(j)=mod(fi(j),2*pi);
if (fi(j)>=fist)*(fi(j)<=fiex)
g=1; % tooth is in the cut
else
g=0; % tooth is out of cut
end
hxx(i)=hxx(i)+g*(Kt*cos(fi(j))+Kn*sin(fi(j)))*sin(fi(j));
hxy(i)=hxy(i)+g*(Kt*cos(fi(j))+Kn*sin(fi(j)))*cos(fi(j));
hxz(i)=hxz(i)+g*(-Kt*sin(fi(j))+Kn*cos(fi(j)))*sin(fi(j));
hyx(i)=hyx(i)+g*(-Kt*sin(fi(j))+Kn*cos(fi(j)))*cos(fi(j));
hyy(i)=hyy(i)+g*(Kt*cos(fi(j))+Kn*sin(fi(j)))*sin(fi(j));
hyz(i)=hyz(i)+g*(Kt*cos(fi(j))+Kn*sin(fi(j)))*cos(fi(j));
hzx(i)=hzx(i)+g*(-Kt*sin(fi(j))+Kn*cos(fi(j)))*sin(fi(j));
hzy(i)=hzy(i)+g*(-Kt*sin(fi(j))+Kn*cos(fi(j)))*cos(fi(j));
hzz(i)=hzz(i)+g*(-Kt*sin(fi(j))+Kn*cos(fi(j)))*cos(fi(j));
end
end
A=zeros(9,9);
A(1,1)=-zeta*w0;
A(1,4)=1/m_t;
A(1,7)=2/m_t;
A(2,2)=-zeta*w0;
A(2,5)=1/m_t;
A(2,8)=3/m_t;
A(3,3)=2*m_t*w0^2*(zeta^2-1);
A(3,6)=zeta*w0;
A(3,9)=3*m_t*w0^2*(zeta^2-1);
A(4,1)=m_t*w0^2*(zeta^2-1);
A(4,4)=-zeta*w0;
A(4,7)=-2*zeta*w0;
A(5,2)=zeta*w0;
A(5,5)=2/m_t;
A(5,8)=5/m_t;
A(6,3)=-zeta*w0;
A(6,6)=1/m_t;
A(6,9)=8/m_t;
A(7,1)=3*m_t*w0^2*(zeta^2-1);
A(7,4)=-zeta*w0;
A(7,7)=2*zeta*w0;
A(8,2)=3*zeta*w0;
A(8,5)=7/m_t;
A(8,8)=6/m_t;
A(9,3)=2*zeta*w0;
A(9,6)=2/m_t;
A(9,9)=5/m_t;
I=eye(size(A));
invA=inv(A); % invA=(A_0)^(-1)
% start of computation
for x=1:stx+1 % sweeping spindle speeds
o=o_st+(x-1)*(o_fi-o_st)/stx; % the spindle speed W
T=60/RVF/o; % time period T
dt=T/k; % time step Dt
% the end of calculation of F_0, F_1, F_2, F_3
Fi0=expm(A*dt); % F_0 in Eq. (3-10)
Fi1=invA*(Fi0-I); % F_1 in Eq. (3-10)
Fi2=invA*(Fi1-dt*I); % F_2 in Eq. (3-10)
Fi3=invA*(2*Fi2-dt*dt*I); % F_3 in Eq. (3-10)
for y=1:sty+1 % sweeping depth of cuts
w=w_st+(y-1)*(w_fi-w_st)/sty; % the depth of cut w
Fi=eye(3*M+6,3*M+6); % construct transition matrix Fi
for i=1:k
B0i=[0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;-w*hxx(i),-w*hxy(i),-w*hxz(i),0,0,0,0,0,0;-w*hyx(i),-w*hyy(i),-w*hyz(i),0,0,0,0,0,0;-w*hzx(i),-w*hzy(i),-w*hzz(i),0,0,0,0,0,0];
B1i=[0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;0,0,0,0,0,0,0,0,0;-w*hxx(i),-w*hxy(i),-2*w*hxz(i),0,0,0,0,0,0;-w*hyx(i),-3*w*hyy(i),-w*hyz(i),0,0,0,0,0,0;-w*hzx(i),-w*hzy(i),-w*hzz(i),0,0,0,0,0,0];
F_i=(Fi1-2*Fi2/dt+Fi3/dt^2)*B0i+...
(Fi2/dt-Fi3/dt^2)*B1i; % F_i in Eq. (3-9)
P_i=(Fi2/dt-Fi3/dt^2)*B0i+...
(Fi3/dt^2)*B1i; % P_i in Eq. (3-9)
R_i=(Fi1-Fi2/dt)*B0i+(Fi2/dt)*B1i; % R_i in Eq. (3-9)
Hi1=inv(I-P_i);
D(1:6,1:6)= Hi1*(Fi0+F_i); % Eq.(3-12)
D(1:6,(3*m(i)+1):(3*m(i)+2),(3*m(i)+3):(3*m(i)+4))=-Hi1*wa(i)*R_i(1:6,1:3);
D(1:6,(3*m(i)+5):(3*m(i)+6),(3*m(i)+7):(3*m(i)+8))=-Hi1*wb(i)*R_i(1:6,1:3);
Fi=D*Fi;
D(1:6,(3*m(i)+1):(3*m(i)+2),(3*m(i)+3):(3*m(i)+4))=0';
D(1:6,(3*m(i)+5):(3*m(i)+6),(3*m(i)+7):(3*m(i)+8))=0';
end
ss(x,y)=o; % matrix of spindle speeds
dc(x,y)=w; % matrix of depth of cuts
ei(x,y)=max(abs(eig(Fi))); % matrix of eigenvalues
end % End of sweeping depth of cuts
stx+1-x
end % End of sweeping spindle speeds
% the end of the proposed mtheod
toc
figure;
contour(ss/10^3,dc/10^(-3),ei,[1,1],'b'),xlabel('Omega_0(Krpm)'),ylabel('w(mm)')
这里的代码非常混乱，算了半天，没看出矩阵D的作用，而且结果ss，dc，ei都是一个数值，怎么能画图呢？请提供相关文献以及源代码出处。
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