求A1、A2、A3的值和A1、A3、A2的关系
A1=(vcc-Vbe)/R1
=(12-0.7)/90
=0.126mA
A2=βA1
=160*0.126
=20.16mA
A3=A1+A2
=0.126+20.16
=20.29mA
A3=A1+A2
A2=β*A2
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A1=(vcc-Vbe)/R1
=(12-0.7)/90
=0.126mA
A2=βA1
=160*0.126
=20.16mA
A3=A1+A2
=0.126+20.16
=20.29mA
A3=A1+A2
A2=β*A2