数学小问题
∫1,-1(1-x^2)dx=[x-1/3x^3]1,-1=2/3+2/3=4/3其中为什么[x-1/3x^3]1,-1=2/3+2/3(1,-1是指∫上下的那两个数字)
这是把积分上下限代入计算的结果:
=[x-1/3x^3]1,-1
=[1-(1/3)*1^3]- [-1-(1/3)*(-1)^3]
=[1-(1/3)]- [-1+(1/3)]
=2/3- [-2/3)]
=2/3+2/3
=4/3
热门标签:
∫1,-1(1-x^2)dx=[x-1/3x^3]1,-1=2/3+2/3=4/3其中为什么[x-1/3x^3]1,-1=2/3+2/3(1,-1是指∫上下的那两个数字)
这是把积分上下限代入计算的结果:
=[x-1/3x^3]1,-1
=[1-(1/3)*1^3]- [-1-(1/3)*(-1)^3]
=[1-(1/3)]- [-1+(1/3)]
=2/3- [-2/3)]
=2/3+2/3
=4/3