若x-y=2,x2-y2=10,则x+y=_______.
解:
x²-y²=10
(x+y)(x-y)=10
将 x-y=2 代入上式:
2(x+y)=10
x+y=5
(8xy2-6x2y)÷(-2x)
=-4y²+3xy
=3xy-4y²
x+y
=(x+y)(x-y)÷(x-y)
=(x²-y²)÷(x-y)
=10÷2
=5
//
(8xy²-6x²y)÷(-2x)
=2xy(4y-3x)÷(-2x)
=-y(4y-3x)
=y(3x-4y)
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