求一个三角函数方程转换!急!sin4x-π/3转化成cos的形式
转化成 cos 函数,周期不变。
sin( 4x-π/3 )
= cos{ 4x + [ π/2 - (-π/3) ] }
= cos( 4x + 5π/6 )
= -cos( 4x + π/6 ) 。
诱导公式:cosa=sin(a+π/2)
sin(4x-π/3)
=cos(4x-π/3-π/2)
=cos(4x-5π/6)
上一篇:1/3:1/6=X:0.2怎么做
热门标签:
转化成 cos 函数,周期不变。
sin( 4x-π/3 )
= cos{ 4x + [ π/2 - (-π/3) ] }
= cos( 4x + 5π/6 )
= -cos( 4x + π/6 ) 。
诱导公式:cosa=sin(a+π/2)
sin(4x-π/3)
=cos(4x-π/3-π/2)
=cos(4x-5π/6)
上一篇:1/3:1/6=X:0.2怎么做