已知xyz≠0且2x3y=3x-8y=z,求(xy-2z)/(x-y2z)的值
已知xyz≠0且2x+3y=3x-8y=z,求(x+y-2z)/(x-y+2z)的值
2x+3y=z..........1
3x-8y=z...........2
1式乘8加2式乘3,得
25x=11z
x=11z/25
代入1式,得
2*11z/25+3y=z
3y=3z/25
y=z/25
所以
(x+y-2z)/(x-y+2z)
=(11z/25+z/25-2z)/(11z/25-z/25+2z)
=(-38z/25)/(60z/25)
=-38/60
=-19/30
热门标签: