初三数学题
化简求值x/x-1÷-[x-x/2x-1]其中x=根号3+1
解:(x-1)/x÷[x-(2x-1)/x]
=(x-1)/x÷[(x²-(2x-1)]/x
=(x-1)/x÷(x-1)²/x
=(x-1)/x*x/(x-1)²
=1/(x-1)
=1/(√3+1-1)
=√3/3
[(x-1)/x]/[x-(2x-1)/x]
=[(x-1)/x]/[(x^2-2x+1)/x]
=[(x-1)/x]/[(x-1)^2/x]
=(x-1)/x*x/(x-1)^2
=1/(x-1)
=1/(根号3+1-1)
=1/3根号3
抱歉我只是一个一小学学生实在帮不到你呀
写清楚些,有时候不懂得你写的
你应该多加几个括号的
两边平方就可以了
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