高等数学偏微分
∂z/∂x=f'(u)*du/dx+f'(v)*dv/dx
=2ulnv*1/y+u^2/v*3
=2*x/y*ln(3x-2y)*1/y+(x^2/y^2)/(3x-2y)*3
=2x/y^2*ln(3x-2y)+3x^2/[y^2*(3x-2y)]
∂z/∂y=f'(u)*du/dy+f'(v)*dv/dy
=2ulnv*(-x)/y^2+u^2/v*(-2)
=2*x/y*ln(2x-3y)*(-x)/y^2+(x/y)^2/(3x-2y)*(-2)
=-2x^2/y^3*ln(3x-2y)-2x^2/[y^2*(3x-2y)]
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