CnH2n+2燃料电池分别在酸性碱性条件下的正负极反应通式
要反应通式,不要个例
酸性:
正极反应:O2 + H+ +4e- ==2H2O
负极反应:CnH2n+2 + 2nH2O - (6n+2)e- == nCO2 + (6n+2)H+
碱性:
正极反应:O2+2H2O+4e- = 4OH-
负极反应:CnH2n+2 + OH- - e- == CO32- + H2O
热门标签:
要反应通式,不要个例
酸性:
正极反应:O2 + H+ +4e- ==2H2O
负极反应:CnH2n+2 + 2nH2O - (6n+2)e- == nCO2 + (6n+2)H+
碱性:
正极反应:O2+2H2O+4e- = 4OH-
负极反应:CnH2n+2 + OH- - e- == CO32- + H2O