二分之负一的二n次方加二分之负一的二n加一次方的结果为(n为正整数)
解:原式=(2分之1)的2n次方+(2分之1)的2n次方×(-2分之1)
=(2分之1)的2n次方×(1-2分之1)
=(2分之1)的2n次方×2分之1
=(2分之1)的2n+1次方
(-1/2)^2n+(-1/2)^(2n+1)
=(-1/2)^2n(1-1/2)
=1/2(1/4)^n
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解:原式=(2分之1)的2n次方+(2分之1)的2n次方×(-2分之1)
=(2分之1)的2n次方×(1-2分之1)
=(2分之1)的2n次方×2分之1
=(2分之1)的2n+1次方
(-1/2)^2n+(-1/2)^(2n+1)
=(-1/2)^2n(1-1/2)
=1/2(1/4)^n